The volume occupied at 0 c and 2atm pressure by the gas evolved from dry ice of volume 8cc (density of dry ice is 1.1gn/ml)
Answers
Answered by
13
Answer:
Explanation:
ANSWER
Given:
Temperature = 0℃ = 273 K; R = 0.0821 L atm/K-mol Pressure = 2 atm
Volume of dry ice = 8 cc = 8 ml
Density = 1.1 g/ml
Given mass of dry ice = Density × Volume = 1.1 × 8 = 8.8 g
According to gas laws, PV=nRT
Molecular weight of dry ice (CO
2
) = 44 g/mol
Now,
n=
MolecularWeight
Givenweight
V=
P
nRT
=
44
8.8
×
2
0.0821×273
=2.24 litres
PLZ MARK AS BRAINILIST
Similar questions