Question

The volume occupied by 0.4 g atoms of o(2) at stp is:

Answer 1

Answer:

Given:

0.4 g of $\rm O_2$

To Find:

The volume occupied by 0.4 g atoms of $\rm O_2$ at STP

(Standard Temperature and Pressure)

Solution:

We know that,

Gram atomic mass of an element is equal to one mole

So,

32 g of $\rm O_2$ atom = 1 mole of $\rm O_2$

Mathematically,

$\rm32\;g \implies 1\;mole\;of\;O_2$

Therefore,

$\rm 0.4\;g \implies x\;moles\;of\;O_2$

Hence,

$\rm \implies x = \dfrac{0.4}{32} \;moles \;of\; O_2$

$\rm \implies x=0.0125\;moles\;of\;O_2$

Hence,

0.4 g of $\rm O_2$ contains 0.0125 moles of $\rm O_2$

According to the Question,

We are asked to find the volume occupied by 0.4 g atoms of $\rm O_2$ at STP

We know that,

1 mole of $\rm O_2$ at STP occupies= 22.4 L (or) 22400 ml

Hence,

⇒ 0.025 mole of $\rm O_2$ will occupy $\rm 22400 \times 0.0125\;ml$

⇒ 0.025 mole of $\rm O_2$ will occupy $\rm280\;ml$

Hence,

The volume occupied by 0.4 g atoms of O₂ at STP is

280 ml