Question

the volume occupied by 1.4g of CO at STP

Answer 1

Volume occupied by 1.4g of CO at STP is 1.12 litres.

For further details check the attachment.

Answer 2

Answer:

The volume of CO occupies 1.12 $dm^{3}$ at STP

Explanation:

Given: The volume occupied by 1.4g of CO at STP

To find: Number of moles of volume occupied at STP

Solution:

Mole:

• The mass of a substance made up of an equal number of fundamental units is referred to as a mole.
• The amount of chemical elements is represented as a mole fraction.
• Mol is the symbol for the unit.

Formula:

$Number of moles = \frac{Mass of substance}{Mass of one mole}$

1 Mole of gas occupy 22.4 Litres of volume at STP.

No. of moles= mass in grams ÷ molar mass

Molar mass:

       The mass in gram of one mole of a substance is its molar mass.

$Number of moles = \frac{mass in grams}{molar mass}$

Mass in gram = 1.4 g

Molar mass of CO = 12 + 16

                              = 28 g

No of moles of CO = Mass in gram ÷ molar mass

                               = $\frac{14 }{28}$

                               = 0.05

As we know that 1 Mole of gas occupy 22.4 Litres of volume at STP.

Therefore 0.5 mol of CO occupies = 0.05 × 22.414

                                                         = 1.12 $dm^{3}$

Final answer

The volume of CO occupies 1.12 $dm^{3}$ at STP

#SPJ2