The volume occupied by 1.7 g of NH3 at S.T.P
Answers
Answered by
3
Explanation:
number of moles of 1.7 g of NH3 = 1.7/17
= 0.1 mol
number of of moles =volume at STP/molar volume
volume at STP = number of moles × molar volume
= 0.1 × 22.4
= 2.24 L
Similar questions