Question

The volume occupied by 17g of H₂S at S.T.P. is what? ( H= 1, S= 32, Molar Volume = 22.4dm³).

Please show with workings

Answer 1

Given:

✰ Atomic mass of H = 1

✰ Atomic mass of S = 32

✰ Molar Volume = 22.4 dm³

To find:

✠ The volume occupied by 17 g of H₂S at S.T.P.

Solution:

Let's understand the concept! First we will calculate relative molecular mass of H₂S, then we know that 17g of H₂S occupied 22.4 dm³ molar volume, so we will use unitary method and find out how much molar volume one gram of H₂S will occupied. After that we will find how much volume will be occupied by 17g of H₂S at S.T.P.

Let's find out...

The relative molecular mass of H₂S

= ( 1 × 2 ) + 32

= 2 + 32

= 34 g

Now,

➛ The volume occupied by 34 g of H₂S = 22.4 dm³

➛ The volume occupied by 1 g of H₂S = 22.4/34

➛ The volume occupied by 1 g of H₂S = 224/(34 × 10)

➛ The volume occupied by 1 g of H₂S = 224/340

➛ The volume occupied by 1 g of H₂S = 56/85

➤ The volume occupied by 17 g of H₂S = 17 × 56/85

➤ The volume occupied by 17 g of H₂S = 952/85

➤ The volume occupied by 17 g of H₂S = 11.2

∴ The volume occupied by 17 g of H₂S = 11.2 dm³

_______________________________