Question

the volume occupied by 18g of water at STP (Density of water is 1 gm/cc) 1) 22.4 lit 2) 18 lit 3) 18 ml 4) 22.4 ml

Answer 1

Answer:

I mole of water has 18gm

so given is 1 mole of water

so it occupies 22.4lit volume

Answer 2

Answer:

The volume occupied by 18g of water at STP will be equal to 18ml.

Therefore, the option (3) is correct.

Explanation:

One mole of water vapor occupied the volume at STP is 22.4 Litres.

The molar mass of water = 18 gmol⁻¹

The volume of water vapors at STP = 22.4 L

Given the mass of water = 18g

Density of water = 1 gm/cc = 1 g/ml

It means  that one gram of water contains 1 ml of water.

Density = Mass/Volume

Volume of water = Mass/density

Volume of water  $=\frac{18g}{1gml^{-1}}= 18ml$

Therefore, 18g of water at STP will be occupied 18ml volume.