The volume occupied by 2 g of a gas at STP, if its vapour density is 56 is
O 0.25 L
0 0.4L
0 1.1 L
O 0.7L
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Given - Weight of gas - 2 gram
Vapour density - 56
Find - Volume occupied by the given gas
Solution - Molecular weight is twice to that of vapour density. Therefore, molecular weight of given gas will be - 2*56 - 112 gram.
At STP, 112 gram of gas weighs 22.4 litre
2 gram of gas will weigh - 22.4/112*2 - 0.4 litre
Hence, 0.4L is the correct answer.
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