Question

The volume occupied by 3.2 g of o, gas at 273 K & 760 mm Hg pressure is:​

Answer 1

Answer:

volume of gas is 2.27L

Explanation:

we know that the ideal gas equation is

pv=nRt

where

p is pressure of gas ,

v is volume of gas

n is number of mole of gas

R is Rydberg constant

t is temperature.

here we have

p=760 mm Hg 1atm=760mmHg

v=? n=mass/molar mass

n=0.1 n=3.2/32. n=0.1

t=273k

R=0.0832atmL/k mol

put this values on the equation

1×v=0.1×0.0832×273

v=2.27L

Answer 2

Answer:

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