Question

the volume occupied by 4.4 gram of seo2 at STP is

Answer 1

this is theanswer forthe question

Answer 2

Hey here is your answer
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Atomic mass of CO2
= 12 + 2 × 16
= 12 + 32
= 44 g

$\\ Volume \: occupied \: by \: 4.4 \: gram \: of \: CO2 \: at \: STP \: \\ \\ = \frac{22.4 \: l \: (stp)}{Atomic\: mass\: of\: compound\: in \: g} \times given \:atomic\: mass\: of\: compound\: in \: g \\ \\ = \frac{22.4 \: l \: (stp)}{44 \: g} \times 4.4 \: g \\ \\ = \frac{22.4 \: l}{44 \: g} \times \frac{44}{10} \: g \\ \\ = \frac{22.4}{10} \: l \\ \\ = 2.24 \: l$
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