The volume occupied by 4.4g of Co2 at STD is
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Hey folk,
Molecular mass of CO2 = 44 g
1 Mol CO2 occupies 22.4l
ie, 44 g CO2 = 22.4 l
so, 4.4 CO2 ( 44 * 0.1 =4.4 ) = 22.4 * 0.1
=2.24 L
Answered by
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Answer:
2.24lit or 22400ml
Explanation:
Weight of CO2 gas is 44g
Weight of CO2 gas is 44g=) Volume occupied by 44g is 22.4lit,
Weight of CO2 gas is 44g=) Volume occupied by 44g is 22.4lit,let , the volume occupied by 4.4g of CO2 be x
Weight of CO2 gas is 44g=) Volume occupied by 44g is 22.4lit,let , the volume occupied by 4.4g of CO2 be x=) x = (22.4×0.1)
Weight of CO2 gas is 44g=) Volume occupied by 44g is 22.4lit,let , the volume occupied by 4.4g of CO2 be x=) x = (22.4×0.1)=) x = 2.24lit
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