the volume occupied by 4.5 g or co². at s.t.p is
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Answer:
The volume of 4.5 g CO2 is 2300 cm3 at STP.
Explanation:
As given,
Mole = Molar massmass=444.4=0.1
VCO2=n×Molar volume=0.1×22.4=2.24 L
Hence, the correct
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