Question

the volume occupied by 8 grams of oxygen at stp

Answer 1

Answer:

11.2

Explanation:

1 mole of O2 = 16 g

0.5 moles of O2 = 8g

{ since n = m/M

where n is the no. of moles

m is the given mass

M is the Molar mass }

We know that at 1 mole of any gas occupies 22.4L at STP.

(or 22.7 according to new STP values)

Then, since 8 g of O gas is 0.5 moles,

0.5 moles of O will occupy 11.2 L

i.e. at STP ==> 0.5 moles = 22.4/2 = 11.2L.

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I hope it helps!

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Answer 2

Answer:

5.6 Liters

Explanation:

o=16 grams per mole.

their are 2 oxegens per o2,

and 8 grams so

8/(16*2)=.25

with 22.4 liters per mole we get

22.4*.25=5.6 Liters

sheroneko's answer forgot to acomidate for the second oxegen.