the volume occupied by 8 grams of oxygen at stp
Answers
Answered by
6
Answer:
11.2
Explanation:
1 mole of O2 = 16 g
0.5 moles of O2 = 8g
{ since n = m/M
where n is the no. of moles
m is the given mass
M is the Molar mass }
We know that at 1 mole of any gas occupies 22.4L at STP.
(or 22.7 according to new STP values)
Then, since 8 g of O gas is 0.5 moles,
0.5 moles of O will occupy 11.2 L
i.e. at STP ==> 0.5 moles = 22.4/2 = 11.2L.
-----------------
I hope it helps!
•●♤♤●•
Answered by
2
Answer:
5.6 Liters
Explanation:
o=16 grams per mole.
their are 2 oxegens per o2,
and 8 grams so
8/(16*2)=.25
with 22.4 liters per mole we get
22.4*.25=5.6 Liters
sheroneko's answer forgot to acomidate for the second oxegen.
Similar questions
Math,
6 months ago
English,
6 months ago
English,
6 months ago
English,
1 year ago
Chemistry,
1 year ago
Computer Science,
1 year ago
Computer Science,
1 year ago