Question

The volume occupied by 88g of Co2 at 30°C and 1 bar pressure will be .......?​

Answer 1

GIVEN

PRESSURE=1 BAR

MASS=88G

G.M.WT OF CO2=44

TEMPERATURE=273+30=303 K

PV=NRT

N=MASS/G.M.WT

PV=$\frac{88}{44}$*0.083*303

PV=50.298

V=50.298

Answer 2

n=88/44 =2mol

T= 30°C = 30+273=303k

P=10^5 pa

by using the formula pv=nRT

v=nRT/p

v=2*303*0.082/10^5

v=4.96*10^-4