Question

The volume occupied by one mole of water is
(density = 1 g/ml)​

Answer 1

Answer:

Explanation:

6.022 ×10^23 molecules =18 g of water

1 molecule= 18/6.022×10^23

=2.98×10^-23g

Density of water=1 g/ml

Volume of 1 molecule of water =mass of 1 molecule of H2O/density

=2.98×10^-23ml

Answer 2

Answer:

density = mass/volume

volume=mass/density

=1 gram/ 1 gram cm⁻³ = 1 cm³

1 g water= 1/18 moles of water

(at wt of H *2 + at wt of oxygen = 18)

volume occupied by 1 molecules of water = (18 / (6.02 x 10²³)) cm³

= 3 x 10⁻²³ cm³