Question

The volume occupied by one molecule of water (density =1gcm^-3) a) 18cm3 b) 22400cm3 c) 6.02×10^-23cm3 d)3×10^-23​

Answer 1

We need to find the Volume occupied by the one molecule of water. The one molecule of water is made up of 2 Atoms of Hydrogen and one atom of Oxygen as ,

$\sf \to Water = \red{ H_2O}$

Therefore the Gram Molecular weight of water is 18g / mol . Now we know that ,

• The Density of water in CGS unit is 1g/cm³
• Also the formula of Density is mass divided by Volume.

• Therefore ,

$\dashrightarrow \sf Density = \dfrac{(Mass)}{(Volume) }\\\\\sf\dashrightarrow Volume = \dfrac{Mass}{\rho}\\\\\sf\dashrightarrow Volume =\dfrac{18g}{1g/cm^3}\\\\\sf\dashrightarrow \boxed{\pink{\sf Volume = 18 cm^3 }}$

Answer 2

Explanation:

We need to find the Volume occupied by the one molecule of water. The one molecule of water is made up of 2 Atoms of Hydrogen and one atom of Oxygen as ,

\sf \to Water = \red{ H_2O}→Water=H

2

O

Therefore the Gram Molecular weight of water is 18g / mol . Now we know that ,

The Density of water in CGS unit is 1g/cm³

Also the formula of Density is mass divided by Volume.

• Therefore ,

\begin{gathered} \dashrightarrow \sf Density = \dfrac{(Mass)}{(Volume) }\\\\\sf\dashrightarrow Volume = \dfrac{Mass}{\rho}\\\\\sf\dashrightarrow Volume =\dfrac{18g}{1g/cm^3}\\\\\sf\dashrightarrow \boxed{\pink{\sf Volume = 18 cm^3 }}\end{gathered}

⇢Density=

(Volume)

(Mass)

⇢Volume=

ρ

Mass

⇢Volume=

1g/cm

3

18g

⇢

Volume=18cm

3