Question

The volume of 0.025 M H2SO4 required to complete neutralise 25ml of 0.03MCa(OH)2 is

Answer 1

The balance reaction of H2SO4 and Ca(OH)2  is as follows:

H2SO4 (aq)  + Ca(OH)2  (aq)  ----- > CaSO4 (s) + 2 H2O (l)

Mole of Ca(OH)2 = Molarity *volume in L

= 0.03 * 25/1000

= 0.0075 moles Ca(OH)2

Now calculate the moles of H2SO4 as follows:  

0.00075 moles Ca(OH)2 * 1 mole H2SO4 /1 moles Ca(OH)2

0.00075 moles H2SO4

Moalrity of H2SO4 = Number of moles / volume in L

Volume in L = 0.00075 moles  / molarity  

= 0.00075 /0.025  

= 0.03 L

= 30  ml H2SO4