Question

the volume of 0.05 N Na2CO3 solution required to neutralize 200ml of 0.02 M H2SO4 solution is

Answer 1

Using N1V1 of base=N2V2 of acid

So, 0.05×x = 0.04×200

x=160 ml.

Answer 2

Answer:

using n1v1 of base n2v2 of acid

so,0.05× × =0.04×200

×=160