The volume of 0.05M K,Cr,0, solution which can oxidise 200ml of 0.1M Feso, solution in acidic medium is
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Answer:
Cr
2
O
7
2−
+
0.6 M/200 mL
FeC
2
O
4
→
H
⨁
Cr
2
O
7
2−
+14H
⨁
+6e
−
→2Cr
3+
+7H
2
O
Fe
2+
→Fe
3+
+e
−
;
C
2
O
4
2−
→2CO
2
+2e
−
FeC
2
O
4
→Fe
3+
+2CO
2
+3e
−
m. Eq.of K
2
Cr
2
O
7
≡m.Eq. of FeC
2
O
4
(0.05×6)×V=(0.6×3)×200
⇒V=1200 mL=1.2 L
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