Question

The volume of 0.1 M Ca(OH), needed for the
neutralization of 40 ml of 0.05 M oxalic acid is
(1) 10 ml
(2) 20 ml
(3) 30 ml
(4) 40 ml​

Answer 1

Answer:

Answer:

20 ml

Explanation:

Dilution law: M1V1=M2V2

$0.1V1=40*0.05</p><p> \\ 0.1V1=2$

Therefore V1=20ml