The volume of 0.1 M H2SO4 required to completely neutralise 10.6 g of Na2 CO3 is
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40 ml of 0.1 m H2SO4
NaOH dissociates as -
NaOH --> Na+ + OH-
Hence, it will produce
[OH] = 0.2 × 40 / 1000 moles
[OH] = 8×10^-3 moles
So We'll need the same amount of H+ ions to neutralize it.
H2SO4 dissociates as -
H2SO4 --> 2H+ + (SO4)2-
Hence, it will produce
[H+] = 2 × 0.1 × x / 1000
8×10^-3 = 2 × 0.1 × x / 1000
x = 40 ml
Therefore, 40 ml of 0.1 m H2SO4 will be required
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