Question

The volume of 0.1 M H2SO4 required to make one litre of 0.001 M H2SO4, solution is​

Answer 1

Explanation:

We know that :

N

1

V

1

=N

2

V

2

Normality=Molarity×Basicity

For sulphuric acid, the basicity is 2.

∴N

1

=0.1×2=0.2N

V

1

= ?

N

2

=0.1×1=0.1N

V

2

=40ml

0.2×V

1

=0.1×40

V

1

=20ml

Answer 2

10 mL of 0.1 M sulphuric acid is required.

Explanation:

To solve this problem, we will use the relationship $M_1V_1 = M_2V_2$

where M terms are representing molarities and V terms are representing volumes of solutions 1 and 2 respectively.

As per the question

$M_1 = 0.1 M$

$V_1 = ?$

$M_2 = 0.001 M$

$V_2 = 1 L = 1000 mL$

Substituting these values in the above expression, we obtain,

$M_1V_1 = M_2V_2$

$0.1\times V_1 = 0.001\times 1000$

$0.1\times V_1 = 1$

$V_1 = \frac{1}{0.1}$

$V_1 = 10 mL$

Hence, 10 mL of 0.1 M sulphuric acid would be required to prepare the desired solution.