Question

The volume of 0.1 MH SO, solution required
to 8 50ml of 0.2M NaoH solution is
1.25ml

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Answer 1

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Answer 2

n-factor of NaOH = 1

n-factor of HCl = 1

As we know, N 1

V 1

=N 2

V 2

(0.1×1)(.02)=(.05×1)×V 2

V 2 =0.04 litre

V 2 =40ml