Question

The volume of 0.1 MH SO, solution required
to neutralize 50ml of 0.2M NaoH solution is
1.25ml


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Answer 1

Answer:

Answer

Correct option is

A

40ml

n-factor of NaOH = 1

n-factor of HCl = 1

As we know, N

1

V

1

=N

2

V

2

(0.1×1)(.02)=(.05×1)×V

2

V

2

=0.04 litre

V

2

=40ml

Answer 2

Answer:

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