Question

the volume of 0.1M oxalic acid

Answer 1

in an acidic medium

5H2C2O4 + 2KMnO4 + 3H2SO4 = K2SO4 +2MnSO4 + 10CO2 + 8H2O

V x M = 0.02 x .025 = 0.0005 (KMnO4)

By balanced equation 2 moles of KMnO4 reacts with 5 moles of acid

1.25 x 10–3 mol react completly

0.1 M x V = 1.25 x 10–3 mol

V = 12.5 mL of acid

hope helped !!!!

Answer 2

25.....................