Question

The volume of 0.5 M h2So4 required for complete neutralization of 10 ml of 0.5 M NaOh is

Answer 1

Answer:

What volume of 0.5 M H2SO4 will exactly neutralize 20 cm3 of 0.1 M NaOH solution?

Start with the equation:

H2SO4(aq)+2NaOH(aq)→Na2SO4(aq)+2H2O(l)

This tells us that 1 mole of acid reacts with 2 moles of alkali.

c=nv

So

n=c×v

So NaOH=0.1×201000=0.002

From the equation you can say that the number of moles of sulfuric acid must be half of this:

H2SO4=0.0022=0.001

Since c = n/v we can say v=n/c so:

v=0.0010.5=0.002L

v=2ml

Answer 2

Answer:

We know that :

N

1

V

1

=N

2

V

2

Normality=Molarity×Basicity

For sulphuric acid, the basicity is 2.

∴N

1

=0.1×2=0.2N

V

1

= ?

N

2

=0.1×1=0.1N

V

2

=40ml

0.2×V

1

=0.1×40

V

1

=20ml