Question

The volume of 1.7g of NH3 at STP (273K, 1atm) isThe volume of 1.7g of NH3 at STP (273K, 1atm) is

Answer 1

Answer:

According to Ideal gas Law

PV=nRT (P-pressure ,V- Volume ,n= moles ,T-Temperature)

17 gm of NH3

Moles of NH3{n}=17÷17=1

Pressure = 1 atm , Temperature= 298K

Applying the Law mentioned above

PV=nRT

1×V=1 ×0.0821×298

V=24.4658 Litres