the volume of 1 gm mole of oxygen is 22400 ml at 760 mm find the temperature of oxygen
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HEYA GM ❤
★ PV = nRT
P = 760 mm Hg = 1atm
V = 22400ml = 22.4 L
moles = 1 / 16
★ T = P V / nR
= 1 × 22.4 × 16 / 0.0821
= 358.4 / 0.0821
= 4365.4 C°
= 4638 K
TQ ❤ ❤
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