The volume of 1 gram mole of oxygen gas is 22400 ml at 760 mm. Calculate the temperature of the gas. (Given, R=0.082 lit-atmos deg ' molº!)
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Answer:
22400 ml of oxygen at 273k
temperature and 3 atm pressure =22400 X 3 = 627 ml at STP.
The number of oxygen molecules present in 22400 ml of gas at STP =N
(Here N is avagadro number )
therefore 224 ml of oxygen at 273k and 3 atm pressure contain =N X 672 /22400 X N molecules .
=3/100 X 6.002 X 10
23
=18.066X10
22 molecule's
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