Question

The volume of 1 L water upon vapourisation at STP is nearly
(1) 124.3 L (2)1244.4 L
(3)1 L (4)22.4 L

Answer 1

Answer : The correct option is, (2) 1244.4 L

Explanation : Given,

Mass of water = 1 L = 1000 g

Molar mass of water = 18 g/mole

First we have to calculate the moles of water.

$\text{Moles of water}=\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{1000g}{18g/mole}=55.55mole$

Now we have to calculate the volume of water at STP.

As we know that at STP,

1 mole of water contains 22.4 L volume of water

So, 55.55 moles of water contains $22.4\times 55.55=1244.4L$ volume of water.

Therefore, the correct option is, (2) 1244.4 L