The volume of 1 molar of hcl and 5 molar hcl to be mixed to get 2 litres of 2 molar hcl are
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Let us suppose that volume of 1MHCl(V1)=xL1MHCl(V1)=xL
So Volume of 5M HCl required to make 2L of 2MHCl(V2)=(2−x)L2MHCl(V2)=(2−x)L
Let us take M1=1MM1=1M and M2=5MM2=5M
We know that
Molarity of the mixture is given by the equation
M1V1+M2V2V1+V2=M3M1V1+M2V2V1+V2=M3
x+5(2−x)2=2x+5(2−x)2=2
x+10−5x=4x+10−5x=4
x=1.5Lx=1.5L
∴∴ Volume of 1M HCl = 1.5L
and Volume of 5MHCl=(2−X)L=(2−1.5L)=0.5L
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