Question

The volume of 2.5 N and 0.625 N acid solution needed should be mixed to prepare 1 litre solution of one normality
O 200 ml and 800 ml
O 400 ml and 600 ml
O 500 ml and 500 ml
O 800 ml and 200 ml​

Answer 1

Answer:

You need to know how much 0.625 N HCl you have. Let’s say you have 500 ml of 0.625 N HCl and you want a liter of 1 N HCl. How much 2.5 N HCl would you have to add

0.625 mol/L x 0.5 L + 2.5 mol/L * x L = 1.0 mol/L x 1.0 L

2.5 x = 1 - (0.625 * 0.5)

x = 0.275 L or 275 mL

Check: 275 x 2.5 + 0.625 x 500 = 1000

687.5 mL+ 312.5 mL = 1000 mL

Explanation:

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