Question

The volume of 2.8g of carbon monoxide at 27°c and 0.0821 atm is pressure

Answer 1

Answer:

pv = NRT (According to Ideal gas equation)

Explanation:

we can cal. the no. of moles of CO i.e

Moles = Given mass = 2.8 = 0.1 mole

Molar mass (12+16)

pressure is given = 0.0821atm

Volume have to be calculated

N is our no. of moles

R is our gas constant - 0.0832

T is 27 degree or we can say 300k

Putting the values

0.0821 × v = 0.1 × 0.0832 × 300

0.0821 × v = 2.496

V = 2.496 ÷ 0.0821

V = 30.4 Litres