Question

The volume of 2 M HCl to be added to 1.8 L of 0.12 M HCl in order to obtain a 0.2 M solution isThe volume of 2 M HCl to be added to 1.8 L of 0.12 M HCl in order to obtain a 0.2 M solution is

Answer 1

Answer:

ok l understood

butcancant answer

Answer 2

Answer:

100g of conc. HCl has 37g of HCl

density is 1.2 g/ml

volume = 100g / 1.2(g/ml) = 83.3 ml = 0.0833 L

n = m/MW n = 37g /34.5(g/mol) = 1.07 moles

[HCl] = 1.07 moles / 0.0833 L = 12.8 M!

V1 x C1 = V2 x C2

12.8M x Xml = 0.025M x 100ml

X = 0.025M x 100ml / 12.8M

X = 0.2 ml of conc.HCl bring to 100 ml with ddH2O

Hope it helps! Good luck!