Question

The volume of 2 m iron rod is 308 m cube Find the circumference of the base.​

Answer 1

$height = 2m \\ rdius(r) = ? \\ volume \: of \: iron \: rode(cylinederical \: shape) = {308}m^{3} \\ \pi \: {r}^{2} h = 308 \\ \frac{22}{7} \times {r }^{2} \times 2 = 308 \\ {r}^{2} = \frac{308}{2} \times \frac{7}{22} \\ {r}^{2} = 49 \\ r = \sqrt{49 } \\ r = 7 \\ circumference \: of \: iron \: rod = 2\pi \: r \\ = 2 \times \frac{22}{7} \times 7 \\ = 44m.$