Question

the volume of 2 m iron rod is 308 meter cube . find the circumference of the base​

Answer 1

GiveN :-

• Volume of the rod = 308 m³

• Height of the rod = 2 m

To FinD :-

• Circumference of the base of rod

SolutioN :-

Firstly we have to find radius of the rod

$\large\longrightarrow \boxed{\bf \orange{ Volume = {\pi r}^{2} h }}$

$\longrightarrow \sf308 = \frac{22}{7} \times {r}^{2} \times 2 \\ \\ \longrightarrow \sf {r}^{2} = 308 \times \frac{44}{7} \\ \\ \longrightarrow \sf{r}^{2} = 1936 \\ \\\longrightarrow \sf r = \sqrt{1936} \\ \\\longrightarrow \sf r = 44 \:m$

Now Circumference of the base of rod

$\large\longrightarrow \boxed{\bf \blue{ Circumference = 2\pi r}}$

$\longrightarrow \sf2 \times \frac{22}{7} \times 44 \\ \\\longrightarrow \sf \frac{1936}{7} \\ \\\longrightarrow \sf 276.5 \: m$

$\large \therefore \: \underline{ \bf \green{Circumference \: of \: rod \: is \: 276.5 \: m }}$

Answer 2

Answer:

The circumference of the base is 44 metres.

Step-by-step explanation:

Given that,

• A 2 metres rod having volume of 308m³.

Here, the rod is cylindrical having height of rod is 2 metres. Therefore, we need to find it's circumstance.

Step 1 :

Finding it's radius :

We know that,

→ Volume of a cylinder : πr²h

• Taking π as 22/7
• h (height) = 2 metres (given)
• "r" is radius

From the given dimensions :

→ 308 = 22/7 × r² × 2

→ 308 = 44/7 × r²

→ 308*7/44 = r²

→ 2156/44 = r²

→ 49 = r²

→ √49 = r

→ r = 7

∴ The radius of the cylinder is 7 metres

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Step 2 :

Finding it's circumstance :

Circumference of the base is given by : → 2πr

• Taking π as 22/7
• r (radius) = 7 metres.

So, Circumstance of the base

→ 2 × 22/7 × 7

→ 2 × 22

→ 44

∴ The circumstance of the base is 44 metres.

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