The volume of 2 spheres are in ratio 64:27 find difference of their surface areas if the sum of their radio is 7
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88 square units
since the volume ratio is 64:27 the radius ratio is 4:3
there sum is 7 so the radio are 4 and 3
surface area of a sphere is 4πr^2
so the difference in there surface area will be 64π -36π which 28π
28π is equal to 88 square units
since the volume ratio is 64:27 the radius ratio is 4:3
there sum is 7 so the radio are 4 and 3
surface area of a sphere is 4πr^2
so the difference in there surface area will be 64π -36π which 28π
28π is equal to 88 square units
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88
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