the volume of 2g of O2 at N.T.P is
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Answered by
49
moles = mass/molecular mass
molecular mass of O2 =32
moles = 2/32
= 1/16
volume = moles * 22.4(in ltr)
= 1/16*22.4
=1.4 ltr
molecular mass of O2 =32
moles = 2/32
= 1/16
volume = moles * 22.4(in ltr)
= 1/16*22.4
=1.4 ltr
Answered by
2
the reaction will always have same ratio of calcium and oxygen . so , if 5:2 of calcium and oxygen after reaction forms calcium oxide then 15:6 of calcium and oxygen will react to form calcium oxide. 6g oxygen reacting with 15g of calcium will form 21g of calcium oxide.
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