the volume of 3/2 m long circular steel rod is 3850m qube. find its diameter
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we know volume of cylinder = (pie)r^2h
then given h = 3/2m
and volume = 3850 m^3
then plugging in the values,
(pie)×r^2×3/2= 3850
pie× r^2 = 3850×2/3
r^2 = 3850×2×7/3×22
so r^2 = 816.666
so r = 28.5777 is your answer
hope this helps you out......
then given h = 3/2m
and volume = 3850 m^3
then plugging in the values,
(pie)×r^2×3/2= 3850
pie× r^2 = 3850×2/3
r^2 = 3850×2×7/3×22
so r^2 = 816.666
so r = 28.5777 is your answer
hope this helps you out......
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