Question

The volume of 4.4 g CO2 at NTP will be ?

Answer 1

weight of carbon dioxide , CO2 = 4.4 g

molecular weight of carbon dioxide , CO2 = 44g/mol

so, number of mole of carbon dioxide = weight of CO2/molecular weight of CO2

= 4.4/44 = 0.1

We know, at normal temperature and pressure , 1 mole of any ideal gas occupies volume 22.4L .

so, volume occupied by 0.1 mole of CO2 at NTP = 22.4 × 0.1 = 2.24 L

hence, answer should be 2.24L

Answer 2

The volume of 4.4 g CO2 at NTP wil be "2.24 L".

Explanation:

Given,

The weight of carbon dioxide (C$O_2$) = 4.4 g and

The molecular weight of carbon dioxide  (C$O_2$) = 12 + 16 × 2

= 44 $\dfrac{g}{mol}$

∴ The number of mole of carbon dioxide = $\dfrac{The weight of CO_2}{The molecular weight of CO_2}$

$= \dfrac{4.4}{44} = 0.1$

We know that,

At normal temperature and pressure (NTP) ,

The volume of 1 mole of ideal gas =  22.4 L

∴ The volume occupied by 0.1 mole of $CO_2$ at NTP

= 22.4 × 0.1

= 2.24 L

Thus, the volume of 4.4 g CO2 at NTP wil be "2.24 L".