Question

The volume of 4.4 g of CO2 gas at 1 atmospheric pressure and 200K temperature will be?​

Answer 1

Answer:

The volume of 4.4 g of $CO_{2}$ gas at 1 atmospheric pressure and 200K temperature will be $1.642 L$

Explanation:

According to the ideal gas equation, $PV=nRT$

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the temperature

Here, P = 1 atm

         T = 200K

         R = 0.0821 atm L/mol K

         Given mass(m) = 4.4 g

we can write the ideal gas equation in terms of molar mass(M) that

$PV =\frac{mRT}{M}$

$V = \frac{mRT}{MP}$

$V = \frac{4.4*0.0821*200}{44*1}$

$V = 1.642 L$

Answer 2

1.644 L

Explanation:

Number of moles (n) = mass/molecular mass

                                    = 4.4/44

                                    = 0.1

Ideal gas equation,

PV = nRT

V = nRT/P

  = 0.1 × 0.0822 × 200/ 1

   = 1.644 L