Chemistry, asked by Lukesan8138, 1 year ago

The volume of 4n hcl and 10 n hcl required to make 1 litre of 6n hcl is

Answers

Answered by nmalavikamohan
76
Let x be the amount of 4N HCl you need. Therefore, 1-x is the amount of 10N HCl you need.

4x + 10(1-x) = 1(6)
4x + 10 - 10x = 6
- 6x = -4
6x = 4
x = 4/6 = 0.67 L

Therefore, 1-x = 1-0.67= 0.33 L

So, you need 0.67 L of 4N HCl and 0.33 L of 10N HCl to make 1 L of 6N HCl.


tiwaavi: There is the mistake in the answer.
tiwaavi: 4/6 is equals to 0.67. U have written 0.8. Wrong. Correct it.
nmalavikamohan: Thank you for pointing out the mistake :)
Answered by tiwaavi
52
Hello Dear.

Here is the answer---

→→→→→→→→→

Let the Volume of the 4 N HCl be x liter.
     N₁ = 4 N

∴ Volume of 10 N HCl = Total Volume - Volume of  4 N HCl
                                   = (1 - x) liter.
     N₂ = 10

Volume of the HCl Produced(V) = 1 liter.
 Normality(N) = 6 N.


We know,

    N₁V₁ + N₂V₂ = NV
⇒  (4)(x) + (10)(1 - x) = (6)(1)
∴ 4x + 10 - 10x = 6
∴ 10 - 6x = 6
∴ 6x = 4
∴ x = 2/3

Thus, the Volume of the 4 N HCl is 2/3 liter.
∴ Volume of the 10 N HCl = 1 - x
                                         = 1 - 2/3
                                         = (3 - 2)/3
                                         = 1/3 liter.

→→→→→→→→→


Hope it helps.

Have a Good Day.

rishilaugh: thanks
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