The volume of 5 moles of methane gas at 273 K and at 1.01325 x 10⁵ Pa pressure will be 8.769 x 10⁻² m³. Calculate compressibility factor. (R= 8.314 J mol⁻¹ K⁻¹)
Answers
Answered by
0
Answer:
Hi this is Nuthuna
Explanation:
Ssolution:-
According to van der Waals equation of state for 1 mole of a gas-
(P+
V
2
a
)(V−b)=0
Since the volume occupied by gas molecules is negligible, i.e.,
b=0
Therefore,
(P+
V
2
a
)V=RT
⇒P=
V
2
RT
−
V
2
a
⇒P=
22.4
0.0821×273
−
(22.4)
2
3.502
⇒P=1.000−0.007=0.993
Similar questions