The volume of 50g of sealed packet is 250cm^3. Will the packet float or sink in the water. If the density of water is 1g cm^3 ? What will be the mass of water displaced by this packet???
Can someone solve this question for me........
Answers
Answered by
0
amount of water displaced = Vdg
=1×250×10
=2500units
=1×250×10
=2500units
Answered by
2
_/\_Hello mate__here is your answer--
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⭐ CONCEPT:-- If the density of an object is more than the density of a liquid, then it sinks in the liquid. On the other hand, if the density of an object is less than the density of a liquid, then it floats on the surface of the liquid.
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Mass of packet, M = 50 g
Volume of packet,V = 250g/cm^3
Dencity of sealed packet =M/V
= 50 /250
= 0.2 g/cm^3
The density of the substance is less than the density of water (1 g/cm3). Hence, it will float on the surface of water.
The mass of water displaced by the packet is equal to the volume of the packet, i.e., 250 g.
I hope, this will help you.☺
Thank you______❤
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