Question

The volume of a 500 g sealed packet is 350 cm³. Will the packet float or sink in water if the density of water is 1 g/cm³? What will be the mass of water displaced by this packet? ​

Answer 1

Given :

• Mass of the packet = 500 g

• Volume of the packet = 350 cm³

• Density of water = $\sf \: 1 \: g \: {cm}^{ - 3}$

To Find :

• Mass of the water displaced & the packet will sink or not

Solution :

★ Density of packet = Mass/Volume

→ Density = $\sf \dfrac{500 \: g}{350{ \: cm}^{3} }$

→ Density = $\sf \: 1.42 \: g \: {cm}^{ - 3}$

Since the density of packet is more than that of water, therefore, the packet will sink in water.

The packet which sinks in water will displace water equal to it's volume. Since the volume of packet is 350 cm³, so it'll displace 350 cm³ of water. Let's calculate the mass of water now :

Now,

★ Density of water = Mass/Volume

→ $\sf \: 1 \: g \: {cm}^{ - 3} = \dfrac{Mass}{350 {cm}^{3}}$

→ Mass = $\sf \: 1 \: g \: {cm}^{ - 3}$ × 350 cm³

→ Mass = 350 g

$\therefore$ Mass of the water displaced by the packet is 350 g.

Answer 2

Answer:

Given : Volume of the packet

V=350 cm³

Mass of the packet

M=500 g

∴ Density of the packet ρ= M/V

= 500/350

=1.43 g/cm³

If the density of packet is greater than that of water, thus it will sink in water.

Mass of water displaced by the packet is equal to the volume of packet times the density of water

=>m(W) =ρ(W)×V

=1×350=350 g

Explanation: