Question

The volume of a 8kg cube is 64cm cube. If this cube is placed on a horizontal surface , find the pressure exerted on the horizontal surface. (Take g = 10m/s square )

Answer 1

volume =64 cm^3

(edge)^3 =64.

edge= 4 cm.

Now, contact area =(edge)^2

area =16 cm^2.

Thrust = mass × g

Thrust = 8 ×10 =80 N.

*Therefore, pressure =Thrust / area.

pressure =80 / 16.

pressure =5 p. a

HOPE ITS HELP YOU

Answer 2

HLO BUDDY HERE IS YOUR ANSWER :-⤵⤵⤵⤵⤵⤵⤵⤵⤵.

Given volume =64 cm^3.

So (a)^3= 64 { a =edge}.

a =4 cm

NOW,

contact area of the cube with ground = (a)^2.

contact area =(4)^2 =16 cm^2. u. area.

Thrust = mass × acceleration due to gravity (g).

Thrust= 8 × 10.

Thrust= 80 N.

Now pressure = Thrust / unit area.

Pressure =80 / 16.

Pressure= 5. p. a✔✔✔✔✔

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