Question

The volume of a certain gas was found to be 1600 cm³ when the pressure was 800 mm, if the volume increased to 80% of the original volume, what is the changed pressure?

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Answer 1

31 mmHg  

Explanation:

Given: V₁ = 1600 cm³, V₂ = ? P₁ = 800 × 0.07 = 56 mmHg , P₂ = ?

    = volume increased by 80 % of the original volume    

    = 1600 × 80/100

    = 1280

V₂ = 1600 + 1280

    = 2880 cm³  

According to Boyle's law

P₁V₁=P₂V₂

P₂ = P₁V₁/V₂

    = 56 × 1600/2880

    = 31 mmHg