the volume of a certain gasat constant tempreature was found to be 900 cm cube under a pressure of760 mm of hg .Calculate the pressure at which volume of gas will be reduced by30% of the original volume while the temperature remaining constant
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Answer:
1085.71 mm of hg
Explanation:
P¹ = 760 mm of hg. V¹ = 900 cm³
p² = ? V² = 900 - 30/100 × 900
= 900 - 270
= 630 cm³
Therefore, Boyl's Law = P¹V¹ = P²V² (temp. remaining constant)
760 × 900 = P² × 630
P² = 760 × 900/ 630
= 684000/ 630
= 1085.71 mm of hg
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