Math, asked by masqur97, 4 months ago

The volume of a chocolate box is 24000 cubic cm. Its length is 60 cm , its height is 40 cm and its breadth is ________ cm.

Answers

Answered by Anonymous
3

Answer❀✿°᭄

Let Z be the number

Z = 13x + 11 where x is the quotient when Z is divided by 13

Z = 17y + 9 where y is the quotient when Z is divided by 17

13x + 11 = 17y + 9

13x + 2 = 17y since x and y are quotients they should be whole numbers . Since y has to be a whole number the left hand side should be multiple of 17

The least possible value of x satisfying the condition is 9 and y will be 7

The answer is 13*9 + 11 = 128 or it is 17*7 + 9 = 128

This is the least number possible. There will be multiple answers and will increase in multiples 17*13 = 221 like 349 , 570, etc

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Answered by Anonymous
7

Answer :-

  • Breadth of the chocolate Box = 10cm.

Given :-

  • Height = 40cm.
  • Length = 60cm.
  • Volume = 24000cm³.

To find :-

  • Breadth.

Step by step explanation :-

Detailed explanation of solution :-

Let's understand!

In the question, Given that, Length = 60cm , Height = 40cm and volume = 24000. we know this, Volume = Length × Breadth × Height.

We are asked to find Breadth.

How to solve ?

To find breadth, We will use this formula :-

 \boxed{ \mathfrak{Volume  \: of  \: box = Height × Breadth × Length}}

Lets use this, And find breadth.

Calculations :-

Volume = length × breadth × height

 \implies \sf 60  \times  40  \times  breath = 24000

 \implies \sf 2400  \times  breadth = 24000

Transposing 2400 from LHS to RHS, Changing sign,

 \implies \sf B =  \dfrac{24000}{2400}

Dividing 24000 by 2400,

 \implies \sf \purple{Breadth = 10 \: cm}

Therefore, Breadth of the chocolate Box is 10cm.

Verification :-

Volume = l × b × h

60 × 40 × 10 = 24000

24000 = 24000

LHS = RHS

Hence , Verified.

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