Question

the volume of a circular iron Rod of length 1 m is 3850 cm find its diameter

Answer 1

volume=πr²h
3850=πr²100
38.5=πr²
385/10=22/7*r*r
385/10*7/22=r²
12.25=r²
So radius is 3.5 CM
and Diameter is 7 CM!

Answer 2

The diameter of the rod is 7 cm.

Step-by-step explanation:

It is given that the volume of a circular iron Rod of length 1 m is 3850 cm³.

1 m = 100 cm

Height = 1 m = 100 cm

Volume = 3850 cm³

Shape of circular iron Rod is cylindrical.

Volume of a cylinder is

$V=\pi r^2h$

where, r is radius and h is height.

Substitute V=3850, $\pi=\frac{22}{7}$ and h=100 in the above formula.

$3850=(\frac{22}{7})r^2(100)$

Multiply both sides by 7.

$26950=2200r^2$

Divide both sides by 2200.

$12.25=r^2$

Taking square root on both sides.

$\sqrt{12.25}=r$

$3.5=r$

The radius of the rod is 3.5 cm. So, the diameter is

$d=2r=2(3.5)=7$

Therefore, the diameter of the rod is 7 cm.

#Learn more

The radius and height of a cylinder are in the ratio of 4:5 and its volume is 2160m. find its diameter and height​.

https://brainly.in/question/13570504