Question

The volume of a circular iron rod of length 1m is 3850 cm cube find its diameter.

Answer 1

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volume of rod (Cylinder) = πr^2h = 3850

h= 1m=100cm

so

r^2= 3850 /(22/7 ×100)

r^2 ===(3850×7)/(22×100)

r^2 === 2695/220

r = √(12.25)

r= 3.5

diameter of the rod is 2×3.5 = 7cm.

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Answer 2

l=1m=100cm
volume0f cylinder=π×r×r×h
22÷7×r×r×100=3850cm
${r}^{2} = \frac{3850 \times 7}{100 \times 22}$
${r}^{2} = \frac{7 \times 7}{2 \times 2}$
$r = \sqrt{ \frac{49}{4} }$
$r = \frac{7}{2} \\ r = 3.5 \\ d = 2 \times r \\ \\ d = 3.5 \times 2 \\ d = 7cm$
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